2x^2+9x+26=4x+5

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Solution for 2x^2+9x+26=4x+5 equation: 



2x^2+9x+26=4x+5

We move all terms to the left:

2x^2+9x+26-(4x+5)=0

We get rid of parentheses

2x^2+9x-4x-5+26=0

We add all the numbers together, and all the variables

2x^2+5x+21=0

a = 2; b = 5; c = +21;
Δ = b2-4ac
Δ = 52-4·2·21
Δ = -143
Delta is less than zero, so there is no solution for the equation

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